Question

An electron.starting from rest,has an acceleration that increases linearly with time;that is,a=kt,in which k=1.50 m/s^3 (a) Plot a versus t during during the first 10-s interval.(b)From the curve of part (a) plot the corresponding v versus t curve and estimate the electron's velocity 5 s after the motion starts.(c) From the v versus t curve of part (b) plot the corresponding x versus t curve and estimate how far the electron moves during the first 5 s of its motion.

Answer 1

a vs t graph will be staright line passing through the origin with slope k.. its just like y=mx..

Answer 2

What about the whole question?

Answer 3

lol. wait. i just read the first part..

Answer 4

for v...
a=dv/dt right?
so dv/dt=kt.. --> dv=kt*dt
integrate both sides..
(delta)v = kt^2/2 .
right?

Answer 5

Dude this looks like a very long question to me so would you just start from the first part.

Answer 6

haha you dont have to be rude man. i see you are an amby too :)

i told you the first part part no? you get it would be a straight line passing through the origin? now what the question asking is.. fir 10 sec interval.. take a couple of values of t.. like 5 sec and 10 sec.. plot them.. and join them with the origin. thats it..

and.. you dont have think this is gonna be a long question. that slows down your brain..

Answer 7

correct^

Answer 8

@yrelhan4

I ain't being rude dude.So chillax.

Okay i get it.

Answer 9

I'm chillen, dont worry about it. :)

And did you get what i did for finding v?
and as it was an indefinite integral.. so no delta(v).. it would be v=1/2 kt^2 .. now plug in values of t. and find the corresponding values of v, and plot..

Answer 10

Well yeah i am getting all of it.

Answer 11

Thats good..
And for the last part.. write v=dx/dt.. integrate again.. plot the graph.. and the question is done.

Answer 12

Thanks a ton.

Answer 13

You're welcome.