A funnel with a height of 3.56 inches is shown below.The funnel has a diameter of 1.38 inches that includes a wall that is 0.125 inches thick. What is the maximum volume of the funnel?
So you have to find the volumes of the cones...
i have to find whats the volume of the cone would be but the thing that is throwing me off is the thickness of the cone ...
Well, I think it's the volume you have to find, so the volume of any cone with radius 'r' and height 'h' is V=πr^3h / 3
v=1/3*pi*r^2*h i have the formula sheet right by me :) haha
1.77= the volume of the whole thing
Depending on what you use for pi (3.14) or (22/7) you get 1.77 or 1.78 These are the answers A)1.19 in3 B)1.78 in3 C)0.76 in3 D)3.57 in3
diameter of 1.38 inches that includes a wall that is 0.125 inches thick. |dw:1368626645955:dw| a diameter of 1.38 means a radius of 1.38/2 = 0.69 but that includes the thickness of the wall. the radius to the inside of the wall is less it is 0.69-0.125 you should use this radius to find the volume of the cone: r= 0.565
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