how to calculate the wavenumber of photon? like we have n=5 and n=2
rydberg formula
I ASKED HOW??? TELL ME THE FORMULA AND ALSO WE HAVE TO APPLY THE SAME FORMULA FOR ALL THE QUESTIONS??
wow relax
if it's for a hydrogen atom, use this
ok thx but Can u plz explain this by this question like n=5 and=2?
|dw:1368626537500:dw| an electron is transiting (falling back down towards the nucleus) and is emitting a photon of energy proportional to the transit. with the formulae i posted, substitute in nf = final ; and ni = initial so ni=5, and nf=2 then solve algebraically
R, rydberg constant, is 1.097x10^5 /cm
this is only if it's for a hydrogen atom, it all little different if it's for another element
thanka a lot!!!!!!!!!!!!!!!!!!
thanks!!!!!!!!!!!
no problem, good luck
thanks my exams are going on!!!
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