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Use differentiation to obtain the slope for equation y = e^3x + e^-3x and calculate the gradient values for the same values of x which are -0.4 and 0.2
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\[y' = 3e ^{3x} - 3e ^{-3x}\] y'(.2) = 3.819 y'(-.4) = -9.056
I got the answer of y = 2.37 (2dp) when x = 0.2
Use differentiation, take the derivative which is y' in my above comment and evaluate it at .2 and -.4.
Just sat through working it out, it makes sense now. I got y = 3.82 (2dp) for when x = 0.2
For some reason, whenever there are e in calculus it always throws me when differentiating.
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