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Mathematics 22 Online
OpenStudy (anonymous):

The data below represent the ages of people working at a store. 17, 25, 18, 24, 18, 22, 30, 21, 18, 17, 19 What is the first quartile of these ages?

OpenStudy (amistre64):

how many ages are there?

OpenStudy (anonymous):

11

OpenStudy (amistre64):

and a quartile is a division by 4 what is 11/4?

OpenStudy (anonymous):

2.75

OpenStudy (amistre64):

since there is not 2.75th position; lets round up to the 3rd position what is the value in the 3rd position if these are sorted low to high?

OpenStudy (anonymous):

18

OpenStudy (amistre64):

then 18 it is ....

OpenStudy (anonymous):

ok,thank you, do you mind if i ask more questions

OpenStudy (amistre64):

feel free, just close this one to type a new question if you want others to "notice" the post and chime in as well

OpenStudy (anonymous):

nah, im good, ill just ask u

OpenStudy (anonymous):

which is equal to square root of 50 5 sqr rt 10 5 sqr rt 2 10 sqr rt 5 25 sqr rt 2

OpenStudy (amistre64):

we can just square the options if need be

OpenStudy (anonymous):

?

OpenStudy (amistre64):

the square of sqrt(50) = 50 so squaring the options would help us determine which option is also equal to 50

OpenStudy (amistre64):

common sense would way they 25^2 and 10^2 are way to big so they can be eliminated

OpenStudy (amistre64):

since 5^2 = 25 we would want to determine which "rt" portion gets us to 25*n = 50

OpenStudy (anonymous):

25 times 2= 50 so would the answer be 5 sqr rt 2, right

OpenStudy (amistre64):

thats right :)

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Ms. Chang has 16 students in her class. She wants to send 3 of her students to pick up books for the class. How many combinations of students can she choose?

OpenStudy (amistre64):

how many choices does she have for the first pick?

OpenStudy (anonymous):

3?

OpenStudy (amistre64):

no, she has 16 children to make a first choice from ....

OpenStudy (anonymous):

o,ok i missread it, but go on

OpenStudy (amistre64):

after making a first choice, how many students are left to make a second choice from?

OpenStudy (anonymous):

13

OpenStudy (amistre64):

no, 16 - 1 = 15 left to choose from

OpenStudy (anonymous):

but she wants to send 3 students so wouldnt you subtract three

OpenStudy (amistre64):

one more kid to pick; now that she has picked 2 kids, from the 16; how many are left to make the last choice from?

OpenStudy (anonymous):

14

OpenStudy (amistre64):

correct :) so what that boils down to is: 16 choices, each with 15 options each: 16*15 each of those options have 14 options each: 16*15*14 is the total number of ways to pick 3 people from a group of 16 but we have duplicates in here since the group: tom, sally, bob is equal to the group: bob, tom, sally so we need to reduce this

OpenStudy (amistre64):

essentially, we want a notation that says: 16 "choose" 3; which is just the setup we had divded by 3!

OpenStudy (amistre64):

16.15.14 -------- 3.2 16.5.7

OpenStudy (anonymous):

ok

OpenStudy (amistre64):

abc = acb = bca = bac = cab = cba .... so there are 6 times as many "same" groups as counted by 16*15*14, so divide it by 6 is all that amounts to

OpenStudy (anonymous):

A jar contains 14 nickels, 10 dimes, 6 quarters, and 22 pennies. A coin is chosen at random from the jar. What is the probability that the coin chosen is a dime?

OpenStudy (amistre64):

since these questions seem to be at random (not related in content), i would rather you close this one and post it as a "new" question on the left.

OpenStudy (anonymous):

y

OpenStudy (amistre64):

thats just how this site operates best. there are a limited number of resources available and a ton of questions being asked. Those who can relate to simpler questions can then field those questions while the more experienced mathikers can focus on the more complicated ones.

OpenStudy (anonymous):

ok,well thank you for youe help

OpenStudy (amistre64):

..and it also helps to spread the fake internet medal wealth about :) good luck

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