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Mathematics 15 Online
OpenStudy (anonymous):

For the data set shown by the table, a. Create a scatter plot for the data. (You do not need to submit the scatter plot) b. Use the scatter plot to determine whether an exponential function or a logarithmic function is the best choice for modeling the data. http://prntscr.com/1507kj

OpenStudy (anonymous):

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OpenStudy (anonymous):

@phi

OpenStudy (phi):

if you connect the dots what does the curve look like ?

OpenStudy (phi):

compare to exponential http://www.purplemath.com/modules/graphexp.htm and logarithmic http://www.purplemath.com/modules/graphlog3.htm

OpenStudy (anonymous):

i think its a log function

OpenStudy (anonymous):

@phi

OpenStudy (phi):

yes, that looks like the best fit of the two choices they give you.

OpenStudy (anonymous):

ok can you give an example of a log function but it should be from the given question to prove our statement

OpenStudy (phi):

I could, but it will take some work to find one that matches your data nicely

OpenStudy (anonymous):

ok

ganeshie8 (ganeshie8):

take the LHS : 1+sec^2xsin^2x

ganeshie8 (ganeshie8):

write sec^2x as 1/cos^2x

ganeshie8 (ganeshie8):

take the LHS : 1+sec^2xsin^2x = 1+ sin^2x/cos^2x = 1+ tan^2x = sec^2x

ganeshie8 (ganeshie8):

take LHS, and use these :- \(\cos(\alpha\ - \beta) = \cos\alpha \cos\beta + \sin\alpha \sin\beta\) \(\cos(\alpha\ + \beta) = \cos\alpha \cos\beta - \sin\alpha \sin\beta\)

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

cos α cos β + sin α sin β) – (cos α cos - β sin α sin β) = 2 sin α sin β 2 sin α sin β = 2 sin α sin β

OpenStudy (anonymous):

is this correct

ganeshie8 (ganeshie8):

LHS = \(\color{green}{\cos(\alpha-\beta)} - \cos(\alpha + \beta)\) = \(\color{green}{\cos\alpha \cos\beta + \sin\alpha \sin\beta} - (\cos\alpha \cos\beta - \sin\alpha \sin\beta)\) = \(\color{green}{\cos\alpha \cos\beta + \sin\alpha \sin\beta} - \cos\alpha \cos\beta +\sin\alpha \sin\beta)\) = \(\cancel{\color{green}{\cos\alpha \cos\beta}} + \sin\alpha \sin\beta \cancel{- \cos\alpha \cos\beta} +\sin\alpha \sin\beta)\) = \(2\sin\alpha \sin\beta\)

ganeshie8 (ganeshie8):

cos terms cancel out, sin terms addup..

OpenStudy (anonymous):

thanks

ganeshie8 (ganeshie8):

np

ganeshie8 (ganeshie8):

any given year, there can be only certain % of students. so it passes vertical line test for a function. so.. ?

OpenStudy (anonymous):

yes

ganeshie8 (ganeshie8):

yes

ganeshie8 (ganeshie8):

its a function cuz no year has 2 different values.

OpenStudy (anonymous):

http://prntscr.com/1563rh

ganeshie8 (ganeshie8):

x-4 cancels out.

ganeshie8 (ganeshie8):

you set the denominator to 0, to get the vertical asymptotes.

ganeshie8 (ganeshie8):

x=0

OpenStudy (anonymous):

so B

ganeshie8 (ganeshie8):

yes

OpenStudy (anonymous):

@ganeshie8

ganeshie8 (ganeshie8):

solve t : 118e0.024t = 140

ganeshie8 (ganeshie8):

once you get t, you need to add it to 1998. to get the actual year

OpenStudy (anonymous):

2005

ganeshie8 (ganeshie8):

where is the q

OpenStudy (anonymous):

@ganeshie8

ganeshie8 (ganeshie8):

did u finish your previous q on population ?

ganeshie8 (ganeshie8):

what did yu get as answer for that

OpenStudy (anonymous):

last answer was 2005

ganeshie8 (ganeshie8):

ohk you solved it good :)

ganeshie8 (ganeshie8):

-404 = -360 - 44 reference angle is the acute angle with x axis

ganeshie8 (ganeshie8):

|dw:1368717426620:dw|

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