For the data set shown by the table, a. Create a scatter plot for the data. (You do not need to submit the scatter plot) b. Use the scatter plot to determine whether an exponential function or a logarithmic function is the best choice for modeling the data. http://prntscr.com/1507kj
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@phi
if you connect the dots what does the curve look like ?
compare to exponential http://www.purplemath.com/modules/graphexp.htm and logarithmic http://www.purplemath.com/modules/graphlog3.htm
i think its a log function
@phi
yes, that looks like the best fit of the two choices they give you.
ok can you give an example of a log function but it should be from the given question to prove our statement
I could, but it will take some work to find one that matches your data nicely
ok
take the LHS : 1+sec^2xsin^2x
write sec^2x as 1/cos^2x
take the LHS : 1+sec^2xsin^2x = 1+ sin^2x/cos^2x = 1+ tan^2x = sec^2x
take LHS, and use these :- \(\cos(\alpha\ - \beta) = \cos\alpha \cos\beta + \sin\alpha \sin\beta\) \(\cos(\alpha\ + \beta) = \cos\alpha \cos\beta - \sin\alpha \sin\beta\)
@ganeshie8
cos α cos β + sin α sin β) – (cos α cos - β sin α sin β) = 2 sin α sin β 2 sin α sin β = 2 sin α sin β
is this correct
LHS = \(\color{green}{\cos(\alpha-\beta)} - \cos(\alpha + \beta)\) = \(\color{green}{\cos\alpha \cos\beta + \sin\alpha \sin\beta} - (\cos\alpha \cos\beta - \sin\alpha \sin\beta)\) = \(\color{green}{\cos\alpha \cos\beta + \sin\alpha \sin\beta} - \cos\alpha \cos\beta +\sin\alpha \sin\beta)\) = \(\cancel{\color{green}{\cos\alpha \cos\beta}} + \sin\alpha \sin\beta \cancel{- \cos\alpha \cos\beta} +\sin\alpha \sin\beta)\) = \(2\sin\alpha \sin\beta\)
cos terms cancel out, sin terms addup..
thanks
np
any given year, there can be only certain % of students. so it passes vertical line test for a function. so.. ?
yes
yes
its a function cuz no year has 2 different values.
x-4 cancels out.
you set the denominator to 0, to get the vertical asymptotes.
x=0
so B
yes
@ganeshie8
solve t : 118e0.024t = 140
once you get t, you need to add it to 1998. to get the actual year
2005
where is the q
@ganeshie8
did u finish your previous q on population ?
what did yu get as answer for that
last answer was 2005
ohk you solved it good :)
-404 = -360 - 44 reference angle is the acute angle with x axis
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