Supply the missing reasons to complete the proof. Given: Angle B is congruent to Angle E and line BC is congruent to line EC.
Prove: line AC is congruent to DC
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OpenStudy (anonymous):
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OpenStudy (anonymous):
@primeralph
OpenStudy (primeralph):
if B = E, and BC = CE, then BE bisects AD
OpenStudy (primeralph):
therefore AC = CD
OpenStudy (anonymous):
Triangle ACB congruent to Triangle DCE
line AC congruent to line DC
Answers :
A CPCTC
B ASA; Substitution
C ASA; CPCTC
D SAS; CPCTC
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OpenStudy (primeralph):
is that all to the question?
OpenStudy (primeralph):
hello?
OpenStudy (anonymous):
I'm sorry i took the dog out and that's the part that i gotta answer the other part is
B is congruent to E and BC is congruent to EC = given
ACD is congruent DCE = vertical angles are congruent
OpenStudy (primeralph):
what is CPCTC? I know SAS
OpenStudy (anonymous):
congruent parts of congruent triangle are congruent
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OpenStudy (primeralph):
D
OpenStudy (anonymous):
What is the value of x ?
|dw:1368637753069:dw|
OpenStudy (primeralph):
180-48. Divide that by 2
OpenStudy (anonymous):
66
OpenStudy (primeralph):
yeah
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