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Geometry 23 Online
OpenStudy (anonymous):

Supply the missing reasons to complete the proof. Given: Angle B is congruent to Angle E and line BC is congruent to line EC. Prove: line AC is congruent to DC

OpenStudy (anonymous):

|dw:1368634506979:dw|

OpenStudy (anonymous):

@primeralph

OpenStudy (primeralph):

if B = E, and BC = CE, then BE bisects AD

OpenStudy (primeralph):

therefore AC = CD

OpenStudy (anonymous):

Triangle ACB congruent to Triangle DCE line AC congruent to line DC Answers : A CPCTC B ASA; Substitution C ASA; CPCTC D SAS; CPCTC

OpenStudy (primeralph):

is that all to the question?

OpenStudy (primeralph):

hello?

OpenStudy (anonymous):

I'm sorry i took the dog out and that's the part that i gotta answer the other part is B is congruent to E and BC is congruent to EC = given ACD is congruent DCE = vertical angles are congruent

OpenStudy (primeralph):

what is CPCTC? I know SAS

OpenStudy (anonymous):

congruent parts of congruent triangle are congruent

OpenStudy (primeralph):

D

OpenStudy (anonymous):

What is the value of x ? |dw:1368637753069:dw|

OpenStudy (primeralph):

180-48. Divide that by 2

OpenStudy (anonymous):

66

OpenStudy (primeralph):

yeah

OpenStudy (anonymous):

Find the value of x. |dw:1368637953958:dw|

OpenStudy (primeralph):

you sure the diagram is right?

OpenStudy (anonymous):

yes

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