Question

which sum is equal to x^2 +6x-5/ x^2-25

Answer 1

@geishaology

Answer 2

@Best_Mathematician help please

Answer 3

Kay.

Answer 4

factor numrator and denominator

Answer 5

Is this a multiple choice or work problem?

Answer 6

yeah it is

Answer 7

That. . .did not answer my question lmao.

Answer 8

@Best_Mathematician
the denominator would be (x-5)(x+5)

Answer 9

I don't know the rest

Answer 10

I don't know

Answer 11

@Best_Mathematician

Answer 12

@hba
@.Sam.
@vivianrush

Answer 13

so what do u say guys

Answer 14

answer is \[\frac{ 1 }{ x+5 } +\frac{ 5 }{ x-5 }+1\]

Answer 15

@Best_Mathematician
I don't have that in my answers

Answer 16

or it should be \[\frac{ x(x+6)-5 }{ (x+5)(x-5) }\]

Answer 17

@Best_Mathematician
can u please check the choices and tell me which one is it
cause that's also non of the choices

Answer 18

@amistre64

Answer 19

@amistre64 I need ur help here plz

Answer 20

it looks like they want you to decompose a fraction ....

Answer 21

I think so

Answer 22

have we factored them yet?

Answer 23

yes

Answer 24

these old eyes cant locate it in the post, can you show me so that i can see if its factored correctly?

Answer 25

the denominator would be (x-5)(x+5)

Answer 26

I don't know the numerator

Answer 27

it's a multiable choice question

Answer 28

i think you have a typo in the numerator

Answer 29

sorry I didn't get it

Answer 30

can you retype the numerator ... i think there might be a mistake in the one you posted

Answer 31

not the options, the problem itself

Answer 32

ok, then we can proceed

Answer 33

this is the equation

Answer 34

so which answer do u think

Answer 35

lets split it up and try to recombine it
\[\frac{x^2-6x+5}{(x-5)(x+5)}=\frac{A}{(x-5)}+\frac{B}{(x+5)}\]
normally we would cross multiply A to B to "solve"
\[x^2-6x+5=A(x+5)+B(x-5)\]
\[x^2-6x+5=Ax+5A+Bx-5B\]
the problem im seeing is that there is no x^2 on the right to compare with

Answer 36

if we simply go with the ropes on this

let x=5
\[\frac{5^2-6(5)+5}{\cancel{(x-5)(x+5)}}=\cancel{\frac{A}{(x-5)}}+\frac{B}{(5+5)}\]
\[B=10(25-30+5)=0\]

let x=-5
\[\frac{(-5)^2-6(-5)+5}{\cancel{(x-5)(x+5)}}=\frac{A}{(-5-5)}+\cancel{\frac{B}{(5+5)}}\]
\[A=-10(25+30+5)=-600\]

Answer 37

and those aint options, so im thinking the problem is simply posted bad to begin with in you material

Answer 38

http://www.wolframalpha.com/input/?i=%28x%5E2-6x%2B5%29%2F%28x%5E2-25%29

the wolf agrees