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@RadEn
f(x)=(x-12)^2 g(x)=x+sqrtx -2\[g(f(x))=f(x)+\sqrt{f(x)}-2=(x-12)^{2}+\sqrt{(x-12)^{2}}-2=x^{2}-23x+130\]
@lexiamee Next time ,try to give a better title .
you could also answer my question. thanks............
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Anonymous answered it above.
I dont understand how . I didnt even know thatwas the answer.
g[f[x]] is got by simply substituting f(x) instead of x in g(x) as shown above
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