Need some help with this calculus question?
It's this:
I've integrated it to get: \[y =\sin 2 \theta \]
is this right, now can I put the limits onto it, being that theta is 0 and pie/4
y=(sin2θ)/2
Is that it at the integrated stage?
if so could you explain how you came by that answer please?
Overall I got y= [0.0137060668 as my final answer.
Take the derivative of his function, you will see that it gives the cosine of 2θ. One formal way to get this is by u-substitution (substitute u for 2θ and du=2dx so du/2 for dx, then integrate)
I'm still confused.
the derivative of \[\sin(2\theta)\] is \[2\cos(2\theta)\] by the chain rule so \(\sin(\theta)\) is not the anti derivative of \(\cos(2\theta)\) the anti derivative of \(\cos(2\theta)\) is \(\frac{1}{2}\sin(2\theta)\)
Just use u substitution if you're unsure \[\Large \int\limits_{0}^{\pi/4} \cos 2 \theta d \theta\] let \[ \large u = 2 \theta\] Try it this way.
Could you do an example of u substitution please?
Try this http://archives.math.utk.edu/visual.calculus/4/substitutions.3/ This first one may be helpful http://archives.math.utk.edu/visual.calculus/4/substitutions.3/int1.html
I'll take a look
y = sin2theta / 2 that's what I got.
That's it.
Ok, so now, With this the limits can be applied to the theta, which is 0 and pie/4. y = [ sin2theta / 2 ]^pie/4 - [ sin2theta / 2 ]^0 y = [ sin2(pie/4) / 2 ] - [ sin2(0) / 2 ] y = [ sin2(0.7853981634) / 2 ] - [ sin2(0) / 2 ] y = [ sin(1.570796327) / 2 ] - [ sin2(0) / 2 ] y = [ 0.02741213359 / 2 ] - [ sin(0) / 2 ] y= [ 0.0137060668 ] - [0 ] y = 0.0137060668 y = 0.013
Your calculator is probably in degrees, those are radians.
Yes it was I degrees. I got y= 0.5 overall as my final answer.
*in
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