Derivative problem, adding equation into reply
\[\frac{\mathrm{d} }{\mathrm{d} y}\frac{y}{4} + \frac{\mathrm{d} }{\mathrm{d} y}\frac{\ y}{\ 4} \ln(\frac{4}{y})\]
OK, take each derivative separately, then add. Is there a section which needs clarification?
Well, according to my mathematics it should compute to \frac{1}{4} + \frac{1}{4}ln(\frac{4}{y})+\frac{y^{2}}{8} but I might be using my product rule wrongly?
\[\frac{1}{4} + \frac{1}{4}\ln(\frac{4}{y})+\frac{y^{2}}{8}\]
Erm... I think you need a chain rule for ln(4/y). Let me check your work...
You got it!
Want, no... the derivative of (4/y) needs to be tacked on to that last term.
So then you get \[\frac{1}{4} + \frac{1}{4}\ln(\frac{4}{y})+\frac{y^{2}}{4}\]
No, the last term should be multiplied by 4 ln(y/4), not just two.
Join our real-time social learning platform and learn together with your friends!