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Mathematics 22 Online
OpenStudy (anonymous):

Math help ! Medals will be given + fan !

OpenStudy (anonymous):

For a standard position angle determined by the point (x,y) what are the values of the trigonometric functions? For the point (16,12) find sin theta and cos theta

OpenStudy (anonymous):

@bahrom7893

OpenStudy (anonymous):

@texaschic101

OpenStudy (anonymous):

@agent0smith

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

this might help

OpenStudy (anonymous):

That helps , but in fractions what would my answer be ?

OpenStudy (anonymous):

OpenStudy (anonymous):

for example ?

OpenStudy (ddcamp):

x = length * cos(theta), y = length * sin(theta) length = sqrt(x² + y²) So: \[\cos(\theta) = \frac{ x }{ \sqrt{x^2 + y^2} } ; \sin(\theta) = \frac{ y }{ \sqrt{x^2 + y^2} }\]

OpenStudy (ddcamp):

Oh, and \[\tan(\theta) = \frac{ y }{ x }\]

OpenStudy (anonymous):

Okay so what is my answer @smartguy1124 & @DDCamp

OpenStudy (anonymous):

i got 9/15

OpenStudy (anonymous):

yeah, but look at my answer choice i just uploaded ?

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

ok yeah then its 9/15

OpenStudy (anonymous):

all of them say 9/15 so what are you saying lol ?

OpenStudy (ddcamp):

Just plug in 16 for x and 12 for y, giving cos(theta) = 0.6 sin(theta) = 0.8 sec(theta) = 1/(cos(theta)) = 15/9 csc(theta) = 1/(sin(theta)) = 5/4

OpenStudy (anonymous):

omg i did it the rong way

OpenStudy (anonymous):

Ya'll are really confusing me. Would my answer be A B C D

OpenStudy (anonymous):

sorry

OpenStudy (anonymous):

okay so scince the cos(theta) = 0.6 that means the answer is 9/15

OpenStudy (anonymous):

thats unless the cos(theta) is rong

OpenStudy (anonymous):

I understand, but everything on my answer choice has 9/15. dId you not see that ?

OpenStudy (ddcamp):

A.

OpenStudy (anonymous):

Are you 100% sure ?

OpenStudy (ddcamp):

Yup

OpenStudy (anonymous):

no

OpenStudy (anonymous):

what is it then ?

OpenStudy (anonymous):

cos 9/15

OpenStudy (anonymous):

i mean csc

OpenStudy (ddcamp):

cos = 9/15, so sec = 15/9

OpenStudy (anonymous):

Okay i don't understand anything that your saying @smartguy1124

OpenStudy (anonymous):

the answer is d

OpenStudy (ddcamp):

@smartguy1124 csc and sec can not ever be less than 1.

OpenStudy (anonymous):

okay which one is it A or D ?

OpenStudy (anonymous):

i know that for sure

OpenStudy (anonymous):

D

OpenStudy (anonymous):

and yes it can @DDCamp

OpenStudy (ddcamp):

Since sin(theta) and cos(theta) will always be between 1 and negative 1, csc(theta) = 1 / sin(theta) can not be between -1 and 1.

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