Can someone help solve this?...
I think its the last one, but they tell me its not
its the last one.
do you understand why?
@Vodka97 yes i understand, but some people on here were telling me it was incorrect
The answer is 3 undefined
do you know how to write the order of a matrix?
@rajee_sam so its not the last one?
NO.
humm.
@rajee_sam @Vodka97 lol see im confused
The order of the matrix is written as ( No. of Rows X No. of Columns). For example the A Matrix has 3 rows and 1 column. So its order is 3 X 1. Similarly the order of B is 2X3. Order of C is 1 X 3 and of D is 3 X 3. So to multiply all of them. You would take two matrices at a time. To be able to multiply Matrix A and B, the no. of Columns of A should be equal to No. of Rows of B. Which is not in this case. So you cannot multiply A and B. So let us Keep A as it is and try and multiply B and C. The no. of Columns of B should Match No. of Rows of C. Which is not same again. So I cannot multiply B and C either. Now consider C and D. Here the No. of Columns of C matches the No. of Rows of D. So I can multiply C and D and the resultant Matrix will be of the Order 1 X 3 which is the No. of Rows of C X No. of Columns of D. So if I multiply the resultant with B I still cannot. So The product is undefined.
As am i. How did you get 3?
@Vodka97 i think he meant the third answer
iknow. but howd he get that.
Read my explanation pl.
@rajee_sam ohhhhhhh ok i see
@rajee_sam theres a rule for that right?
@rajee_sam thanks man! :D
So to multiply 2 Matrices, b4 you get into the work do the simple check if they can be multiplied or not. It will save you the trouble, because Matric multiplication is Boooooring..
yes that is the rule. If you say A times B in Matrix the order cannot be changed. You have to write A first and then B. Then you check if No. of columns of A is equal to the No. of Rows of B. If not then they cannot be multiplied.
Did they say your answer is right now?
whoever "They " is>>>
kkk
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