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dy/dx = 2x - 7, y(2) = 0
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x^2/2 - 7x?
not sure what to do after that
it is \[\frac{ 2x ^{2} }{ 2 } - 7x + c = x ^{2} - 7x + c\]
Now they have given y(2) = 0. Use this information to find 'c'
\[f(x) = 2x - 7, F(x) = x² - 7x + C\] \[F(2) = 0 = 2^2 -7(2) + C = 4 - 14 + C = -10 + C \rightarrow C = 10\] \[F(x) = x^2 - 7x + 10\]
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ty ty
ok so u did x^2 - 7x + c = 0?
@rajee_sam
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