Question

Multiply (3 + 2i)(-1 + 4i).

Answer 1

is this a complex equation the 2i and 4i part?

Answer 2

yes

Answer 3

ok give me a minute it been a while doing this by hand.....easier with a calculator

Answer 4

ok so this is what you have
\[(3+2i)(-1+4i)\rightarrow-3+12i-2i-8\rightarrow-11+10i\]

when you use the foil method and you multiply the 2i and 4i together you get \[8i^2=-8\] remember that. the negative sign will always apply when you multiply two complex roots together
so your final answer will be \[-11+10i\] just like i got above

Answer 5

Solve using the Quadratic Formula.
2x2 + 3x - 6 = 0

Answer 6

do you know the quadratic eq?

Answer 7

no

Answer 8

ok so you have \[ax^2+bx+c=0\]

and from the problem you are solving from you can tell what your a,b, and c value is

now the quadratic equation is \[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

use that formula to solve for your x values. you will have 2 x values

Answer 9

thank you

Answer 10

welcome anytime