Question

x^2+4x+1=0

Answer 1

easiest to complete the square for this one

Answer 2

how do you do it???

Answer 3

what are you asking for

Answer 4

start by subtracting
(1\) from both sides to get
\[x^2+4x=-1\]
then complete the square
half of 4 is 2, and \(2^2=4\) so you can rewrite this as
\[(x+2)^2=-1+4=3\]

Answer 5

i don't know how to complete the square!! help

Answer 6

once you have
\[(x+2)^2=3\] you know
\[x+2=\pm\sqrt{3}\] and so
\[x=-2\pm\sqrt{3}\] are your two answers

Answer 7

wait can you factor this equation too

Answer 8

once again
steps look like this
\[x^2+4x-1=0\]
\[x^2+4x=-1\]
\[(x+2)^2=-1+4=3\]
\[x+2=\pm\sqrt3\]
\[x=-2\pm\sqrt3\]

Answer 9

you can also use the quadratic formula to solve
\[ax^2+bx+c=0\] then
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] in this case you have
\[x^2+4x+1=0\] so \[a=1,b=4,c=-1\] plug in and get
\[x=\frac{-4\pm\sqrt{4^2-4\times 1\times 1}}{2}\] but this is more work