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@satellite73 @bahrom7893
you need the third side
what is the third side ?
you can find it by pythagoras \[a^2+15^2=25^2\] etc or you can recognize this as a 3 - 4 - 5 right triangle with each side multiplied by 5, the third sides is \(20\)
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that third side
ABCD
btw i guess it did not occur to the moron who wrote this question that \[\frac{15}{25}=\frac{3}{5}=.6\] but no matter
i would say b
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secant is "hypotenuse over adjacent" so \(\frac{25}{20}=\frac{5}{4}\) for that one
tangent is opposite over adjacent so \(\frac{15}{20}=\frac{4}{5}\) for that
cosine is adjacent over hypotenuse. for angle Z it would be \(\frac{15}{25}=\frac{3}{5}\)
so would my answer be b ?
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