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OpenStudy (ddcamp):
Start by squaring both sides.
OpenStudy (anonymous):
i do not know how to do that, help?
OpenStudy (anonymous):
\[4=\sqrt{p - 2}\]
OpenStudy (anonymous):
yes thats it ^
OpenStudy (ddcamp):
\[(\sqrt{n})^2 = n, so (\sqrt{p-2})^2 = p-2\]
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OpenStudy (anonymous):
ok now what?
OpenStudy (anonymous):
\[4 = \sqrt{p - 2}\]
\[(4)^2 = (\sqrt{p - 2})^2\]
OpenStudy (anonymous):
so (4)^2 = ?
OpenStudy (anonymous):
16
OpenStudy (anonymous):
\[16 = p - 2\]
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OpenStudy (anonymous):
since:
\[ (\sqrt{p - 2})^2 \rightarrow p - 2\]
OpenStudy (anonymous):
????
OpenStudy (anonymous):
what?
OpenStudy (anonymous):
im lost
OpenStudy (anonymous):
@DDCamp showed you the rule
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OpenStudy (anonymous):
the \[\sqrt{?}\] and the ^2 cancel out so it just becomes p - 2
OpenStudy (anonymous):
my answeer choices ar: a. \[\sqrt{6}\] b.36 c.3 d.6 can you help me get one of those? im way behind and math confuses me
OpenStudy (anonymous):
and ohh ok so its 16=p-2
OpenStudy (anonymous):
what do you do from there?
OpenStudy (anonymous):
we want to get p by itself.
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OpenStudy (anonymous):
so we have to add 2 to both sides
OpenStudy (anonymous):
try it
OpenStudy (anonymous):
so 18=p ?
OpenStudy (anonymous):
yea
OpenStudy (anonymous):
now what?
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OpenStudy (anonymous):
is the answer 36?
OpenStudy (anonymous):
did you write the question right?
or is it:
\[4 = \sqrt(p)-2\]
OpenStudy (anonymous):
i wrote it write
OpenStudy (anonymous):
hm so if it is like you said:
\[4 = \sqrt{p - 2}\]
then the answer is 18
----------------------------------------------
\[4 = \sqrt{18 - 2}\]
\[4 = \sqrt{16}\]
\[4 = 4\]
TRUE
OpenStudy (anonymous):
so either you wrote the problem wrong OR the something is wrong with the choices cuz 18 is not a choice.
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OpenStudy (anonymous):
i dont have that answer to choose from
OpenStudy (anonymous):
okaii?
OpenStudy (anonymous):
i know.
OpenStudy (anonymous):
can you help me with another problem?
OpenStudy (anonymous):
i will try
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OpenStudy (anonymous):
\[\sqrt{q-9}=17\]
a.40
b.16
c.58
d.23
OpenStudy (anonymous):
follow the same steps
OpenStudy (anonymous):
so
\[\sqrt{q-9^{2}}=17^{2}\]
q-9=289?
OpenStudy (anonymous):
not quite.
\[\sqrt{q - 9} = 17\]
use paranthesis
\[(\sqrt{q - 9})^2 = (17)^2\]
OpenStudy (anonymous):
well you got the calculations right
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OpenStudy (anonymous):
but the notation is not correct :)
OpenStudy (anonymous):
\[(\sqrt{q - 9})^2 = (17)^2\]
\[q - 9 = 289\]
OpenStudy (anonymous):
so now what?
OpenStudy (anonymous):
you want to get q by itself.
so what do you do to both sides to get rid of the -9?
you add 9 to both sides
OpenStudy (anonymous):
\[q - 9 + 9 = 289 + 9\]
\[q = 289 + 9\]
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