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Mathematics 13 Online
OpenStudy (anonymous):

4=sqrtp-2

OpenStudy (ddcamp):

Start by squaring both sides.

OpenStudy (anonymous):

i do not know how to do that, help?

OpenStudy (anonymous):

\[4=\sqrt{p - 2}\]

OpenStudy (anonymous):

yes thats it ^

OpenStudy (ddcamp):

\[(\sqrt{n})^2 = n, so (\sqrt{p-2})^2 = p-2\]

OpenStudy (anonymous):

ok now what?

OpenStudy (anonymous):

\[4 = \sqrt{p - 2}\] \[(4)^2 = (\sqrt{p - 2})^2\]

OpenStudy (anonymous):

so (4)^2 = ?

OpenStudy (anonymous):

16

OpenStudy (anonymous):

\[16 = p - 2\]

OpenStudy (anonymous):

since: \[ (\sqrt{p - 2})^2 \rightarrow p - 2\]

OpenStudy (anonymous):

????

OpenStudy (anonymous):

what?

OpenStudy (anonymous):

im lost

OpenStudy (anonymous):

@DDCamp showed you the rule

OpenStudy (anonymous):

the \[\sqrt{?}\] and the ^2 cancel out so it just becomes p - 2

OpenStudy (anonymous):

my answeer choices ar: a. \[\sqrt{6}\] b.36 c.3 d.6 can you help me get one of those? im way behind and math confuses me

OpenStudy (anonymous):

and ohh ok so its 16=p-2

OpenStudy (anonymous):

what do you do from there?

OpenStudy (anonymous):

we want to get p by itself.

OpenStudy (anonymous):

so we have to add 2 to both sides

OpenStudy (anonymous):

try it

OpenStudy (anonymous):

so 18=p ?

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

now what?

OpenStudy (anonymous):

is the answer 36?

OpenStudy (anonymous):

did you write the question right? or is it: \[4 = \sqrt(p)-2\]

OpenStudy (anonymous):

i wrote it write

OpenStudy (anonymous):

hm so if it is like you said: \[4 = \sqrt{p - 2}\] then the answer is 18 ---------------------------------------------- \[4 = \sqrt{18 - 2}\] \[4 = \sqrt{16}\] \[4 = 4\] TRUE

OpenStudy (anonymous):

so either you wrote the problem wrong OR the something is wrong with the choices cuz 18 is not a choice.

OpenStudy (anonymous):

i dont have that answer to choose from

OpenStudy (anonymous):

okaii?

OpenStudy (anonymous):

i know.

OpenStudy (anonymous):

can you help me with another problem?

OpenStudy (anonymous):

i will try

OpenStudy (anonymous):

\[\sqrt{q-9}=17\] a.40 b.16 c.58 d.23

OpenStudy (anonymous):

follow the same steps

OpenStudy (anonymous):

so \[\sqrt{q-9^{2}}=17^{2}\] q-9=289?

OpenStudy (anonymous):

not quite. \[\sqrt{q - 9} = 17\] use paranthesis \[(\sqrt{q - 9})^2 = (17)^2\]

OpenStudy (anonymous):

well you got the calculations right

OpenStudy (anonymous):

but the notation is not correct :)

OpenStudy (anonymous):

\[(\sqrt{q - 9})^2 = (17)^2\] \[q - 9 = 289\]

OpenStudy (anonymous):

so now what?

OpenStudy (anonymous):

you want to get q by itself. so what do you do to both sides to get rid of the -9? you add 9 to both sides

OpenStudy (anonymous):

\[q - 9 + 9 = 289 + 9\] \[q = 289 + 9\]

OpenStudy (anonymous):

so 298? now what... thats not one of the answer?

OpenStudy (anonymous):

well thats the answer

OpenStudy (anonymous):

im telling you, you might have written it wrong.

OpenStudy (anonymous):

the answer was 58... and the first one was 36...

OpenStudy (anonymous):

yeah i know it was 36 but you had wrote it wrong!

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