Question

A stadium has 52,000 seats. Seats sell for $42 in section A, $36 in section B, and $30 in section C. The number of seats in section A equals the total number of seats in sections B and C. Suppose the stadium takes in $1,960,200 from each sold out event. How many seats does each section hold?

Answer 1

Total seats = A + B + C
Total sales = 42(A) + 36(B) + 30(C)
A = B + C

Solve the system of equations.

Answer 2

I dont follow w how to set it up

Answer 3

A is the number of seats in section A
B is the number of seats in section B
C is the number of seats in section C

There are 52000 seats total, so
52000 = A+B+C

There are the same number of seats in section A as in B and C combined, so
A = B + C

Using the ticket price for seats in each area, and the sales when all the seats are full:
1960200 = 42(A) + 36(B) + 30(C)

Answer 4

Easiest start is:
52000 = A + (B+C); A = B+C → 52000 = 2A → 26000 = A

With that, finding B and C should be fairly straightforward.

Answer 5

Thanks, trying this now.

Answer 6

total sales = 42(B+C) + 36B + 30C
so $1,960,200 = 42B + 42C + 36B + 30C or 78B + 72C

Answer 7

Confused.

Answer 8

B=A-26000 is as far as I've gotten lol

Answer 9

B=C-2600

Answer 10

B=C-26000

Answer 11

C+B+26000=52000