What is a quartic function with only the two real zeros given? x = -4 and x = -1 A. y = x4 + 5x3 + 5x2 + 5x + 4 B. y = x4 - 5x3 - 5x2 - 5x - 4 C. y = -x4 + 5x3 + 5x2 + 5x + 4 D. y = x4 + 5x3 + 5x2 + 5x - 5
@Forever_Me @rajee_sam
For this, the factors must be (x+1)(x+4) to make it equal zero at both indicated values.
I didn't get it
@Numb3r1
he is asking for Quartic function it has only 2 real zeros
To make x=-4 and x=-1 give zero when fed through the function, (x+1)(x+4) must be the factorization of the equation. There must also be either a quadratic equation without any real zeros or more of those same factors.
So other 2 are complex
All I can think of is use synthetic division to divide all the 4 answer choices to see which one has both -1 and -4 as its zeros and then examine the quotient to see which one has complex roots
he is asking which eqution has only the givin zeros -1 -4
It isn't too hard to multiply those factors, then use synthetic division to test that. It'll save a little bit of work that way.
It is very laborious but I cannot think of any other way now.
I'd divide by the quadratic, is what I'm saying. It saves a step of division.
guys I really don't know how to do this so can u help me figure out what is the answer
I cannot do synthetic then, I would have to do long division once I multiply them.
Ok do you know how to do synthetic division?
Why not? It's one division instead of two.
I'm really confused
Once you multiply the two factors it will be a trinomial. Can I do synthetic with a trinomial divisor? We will help you out malka in a bit just hang on. Thinking of a less tedious way to do it.
you would have to do the long division
Ok here is what we will do. If x=-4 and x=-1 are zeroes. Then x+4 and x+1 are factors . Do you agree @malkassir
yes
So now multiply those.
Now let us multiply the two together : (x+1)(x+4) = x^2 + 5x + 4
ok
Now we're going to do long division:
Now take that and divide all the 4 answer choices. Once you divide it should divide completely without a remainder because they are a factor
Here are your original options: A. y = x4 + 5x3 + 5x2 + 5x + 4 B. y = x4 - 5x3 - 5x2 - 5x - 4 C. y = -x4 + 5x3 + 5x2 + 5x + 4 D. y = x4 + 5x3 + 5x2 + 5x - 5
@Numb3r1 , I will do A and show him how to do it.
okay I will do B and @Numb3r1 you do c and we will see which one is right
Here's a drawing to start all of them off:|dw:1368677592658:dw|
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