Question

What are all the real zeros of y = (x - 12)3 - 10?

Answer 1

@nathan917

Answer 2

@rajee_sam

Answer 3

@Numb3r1

Answer 4

If you plug each of those into the equation, you'll see which ones produce zero.

Answer 5

Frankly, only one of them makes sense.

Answer 6

However, there will probably be other zeros than those listed. For that, I'll expand it, but take a look at those first and see which one works.

Answer 7

\[(x-12)^{3} -10 = 0\]\[(x-12)^{3} =10\]\[(x-12) = \sqrt[3]{10}\]\[x = \sqrt[3]{10} + 12\]

Answer 8

I tried A and it worked it was =0

Answer 9

Now, there still may be other zeros from more subtle factorizations, but if you are only asked which of those options is a zero of the function, A is correct.

Answer 10

\[(x-12)^3+10=x^3-36x^2+432x-1728+10=x^3-36x^2+432x-1718\] I don't know if that was all you were asked for, but if there are more roots they'll be roots of this equation.

Answer 11

That's the only root. Tested and true.