how to do these surd equations? x-1 = square root 5x-9 x-3 = square root 30 - 2x
\[x-1 = \sqrt{5x-9}\]
and \[x-3 = \sqrt{30-2x}\]
the question is to solve for x and y ?
No, just for x
Well... the seemingly natural way to do it is to square both sides of the equation...
Take the first one, for instance... \[\Large (x-1)^2 = \left(\sqrt{5x-9}\right)^2\] Squaring would cancel the radical, leaving you with... \[\Large x^2 -2x + 1 = 5x -9\]
for the first one x=5 ans x=2
you just have to square both sides first then factorize the square
and for the second one x=7 and x=-3
did that make sense ?
is there meant to be two solutions for those questions?
yeah
cuz when square both side you will get x^2 in the left side and thar tells there are two independent solutions for the equation
can you show me your working because i got a completely different answer
sure just a sec
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