how to do these surd equations?
x-1 = square root 5x-9
x-3 = square root 30 - 2x
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OpenStudy (anonymous):
\[x-1 = \sqrt{5x-9}\]
OpenStudy (anonymous):
and \[x-3 = \sqrt{30-2x}\]
OpenStudy (anonymous):
the question is to solve for x and y ?
OpenStudy (anonymous):
No, just for x
terenzreignz (terenzreignz):
Well... the seemingly natural way to do it is to square both sides of the equation...
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terenzreignz (terenzreignz):
Take the first one, for instance...
\[\Large (x-1)^2 = \left(\sqrt{5x-9}\right)^2\]
Squaring would cancel the radical, leaving you with...
\[\Large x^2 -2x + 1 = 5x -9\]
OpenStudy (anonymous):
for the first one x=5 ans x=2
OpenStudy (anonymous):
you just have to square both sides first then factorize the square
OpenStudy (anonymous):
and for the second one x=7 and x=-3
OpenStudy (anonymous):
did that make sense ?
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OpenStudy (anonymous):
is there meant to be two solutions for those questions?
OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
cuz when square both side you will get x^2 in the left side and thar tells there are two independent solutions for the equation
OpenStudy (anonymous):
can you show me your working because i got a completely different answer
OpenStudy (anonymous):
sure just a sec
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