What is the equation of the ellipse with foci at (5, 0), (-5, 0) and vertices (9, 0), (-9, 0)?
Answers:
x2/81+y2/25=1
x2/81-y2/25=1
x2/81+y2/56=1
x2/81-y2/56=1
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OpenStudy (anonymous):
@yrelhan4
OpenStudy (yrelhan4):
coordinates of focii are (+/-ae,0).. and coordinates of vertices are.. (=/-a,0).. and e=sqrt(1-[(b/a)]^2).. using the first two. find the value of e.. once you have e.. using the third relation find the value of b.. once you have a and b.. you can easily check which equation satisfies..
OpenStudy (yrelhan4):
where 2a=length of major axis.. 2b=length of minor axis.. e=eccentricity.
i hope you know these terms..
OpenStudy (anonymous):
yea I do My answer that I got is A
OpenStudy (yrelhan4):
hmm. give me a minute.
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OpenStudy (yrelhan4):
i am not able to solve it for some reason.. lets solve together and tell me where i'm going wrong..
OpenStudy (yrelhan4):
so.. ae=5 and a=9.. right?
OpenStudy (anonymous):
yea
OpenStudy (yrelhan4):
e=5/9=sqrt(1-(b^2/a^2))..
OpenStudy (yrelhan4):
--> b^2/a^2=1-25/81..
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OpenStudy (yrelhan4):
=56/25 --> b^2=56..
OpenStudy (yrelhan4):
oh wait.. oh i did that wrong..
OpenStudy (yrelhan4):
b^2/a^2=56/81 -->b^2=56..
OpenStudy (yrelhan4):
so your answer should be C..
OpenStudy (anonymous):
I see where I made my mistake Thank You
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