Question

square root 2x+6 - square root x+4 =1

Answer 1

\[\sqrt{2x+6}-\sqrt{x+4}=1\]

Answer 2

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Answer 3

\[\sqrt{2x+6}-\sqrt{x+4}=1\]
Square both sides.
\[(\sqrt{2x+6}-\sqrt{x+4})^2=1^2\]
\(2x+6-2\sqrt{2x+6}\sqrt{x+4}+x+4=1\) \(((a-b)^2=a^2-2ab+b^2)\)
\(3x+10-1=2\sqrt{2x+6}\sqrt{x+4}\)
\(3x+9=\sqrt{(2x+6)(x+4)}\)
Square both sides.
\((3x+9)^2=(\sqrt{(2x+6)(x+4)})^2\)
\(9x^2+54x+81=2x^2+14x+24\)
\(9x^2+54x+81-2x^2-14x-24=0\)
\(7x^2+40x+57=0\)
Nw try to solve this quadratic equation.
Does that help? @Lii

Answer 4

thanks alot, it helped alot to get started

Answer 5

Welcome:)
To solve the quadratic equation, u can use quadratic formula.
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
the values of a.b and c can be found by comparing the equation \(7x^2+40x+57=0\) with the general equation \(ax^2+bx+c=0\)

Answer 6

i got -2.7143 and -3

Answer 7

perfect:)