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Mathematics 11 Online
OpenStudy (anonymous):

You have checked out b books from the library, where b is a number greater than 5. You plan to read three of the books and return them at the end of this week. In how many ways can you pick the books you will read first, second, and third?

OpenStudy (anonymous):

b3 ways?

OpenStudy (hunus):

What do you mean by b3?

OpenStudy (anonymous):

b to the third

OpenStudy (hunus):

Oh, nope. Are you working with permutations and combinations yet?

OpenStudy (anonymous):

Nonlinear Functions and Polynomials

OpenStudy (anonymous):

(b3 - 3b2 + 2b) ways?

OpenStudy (anonymous):

I realy just want to learn how to solve this so i don't have to guess.

OpenStudy (hunus):

Yup

OpenStudy (hunus):

That's correct

OpenStudy (anonymous):

My guess was right?

OpenStudy (hunus):

Say for instance b was equal to ten, for your first book you would have 10 choices for your second book you would have 9 choices and for your third book you would have 8 choices So you would have 10*9*8 = 720 ways of choosing the three books you would read if there were 10 total

OpenStudy (hunus):

So if you had b books, how many choices would you have after you chose one?

OpenStudy (anonymous):

b-1

OpenStudy (hunus):

and after you chose that one?

OpenStudy (anonymous):

b-2

OpenStudy (hunus):

So how many choices would you have overall?

OpenStudy (anonymous):

well, it says be is a number greater than 5. eh,.. 6?

OpenStudy (anonymous):

1 * 2 * 3 right?

OpenStudy (hunus):

If you have 3 books of which you can choose two from then you have 3 choices for your first book and then 2 choices for your second book, so overall you have 3*2 = 6 different ways you can choose your two books |dw:1368690094521:dw|

OpenStudy (hunus):

So you would have b(b-1)(b-2) ways to choose your books

OpenStudy (anonymous):

hey thanks i was kinda right but I don't think my reasoning would work in all circumstanses.

OpenStudy (hunus):

Yup :)

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