Question

A fireworks company has two types of rockets called Zinger 1 and Zinger 2. The polynomial -16t2 + 150t gives the height in feet of Zinger 1 at t seconds after launch. The polynomial -16t2 + 165t gives the height of Zinger 2 at t seconds after launch. If the rockets are launched at the same time and both explode 6 seconds after launch, how much higher is Zinger 2 than Zinger 1 when they explode?

Answer 1

What is the height of both of the rockets at t = 6?

Answer 2

sorry tring to wrap my head around this one.

Answer 3

t= time?

Answer 4

Yup

Answer 5

Here's a picture of their graphs

Answer 6

zinger 1= 406, zinger 2 = 421

Answer 7

Id have to say 90 secounds beased on the answers given to me.

Answer 8

I mean feet

Answer 9

You're around the right numbers

\[Z_{1}=-16t^2+150t\]
\[Z_{2}=-16t^2+165t\]
so at t=6 we will have
\[Z_{1}=-16*6^2+150*6 = -16*36+900 = 900 - 576= 324\]

Answer 10

That's a good guess. Try calculating zinger 2's height and seeing their heigh difference

Answer 11

lol i was way off again. let me re read that see if I can't figure that out.

Answer 12

where did you get 900 from?

Answer 13

150*6

Answer 14

oh okay gotchya.

Answer 15

Did you get it?

Answer 16

I did thankyou