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Physics 9 Online
OpenStudy (anonymous):

A space ship travels to Alpah Centauri which is about 4 light years away from earth. How far does this distance appear to you if you are on a space ship traveling at .99c?

OpenStudy (anonymous):

@shamim

OpenStudy (shamim):

i think it will b the same formula

OpenStudy (shamim):

\[L=L _{0}\sqrt{1-\frac{ v ^{2} }{ c ^{2} }}\]

OpenStudy (anonymous):

what do L and L0 = ?

OpenStudy (anonymous):

@shamim

OpenStudy (shamim):

\[L _{o}=4 ly\]

OpenStudy (shamim):

we hv to calculate L

OpenStudy (anonymous):

then what would v=?

OpenStudy (anonymous):

@Compassionate

OpenStudy (compassionate):

v = the velocity relative c= speed of light

OpenStudy (compassionate):

c = the speed of light L0 = proper length L = length at speed v v = speed of the rocket

OpenStudy (compassionate):

You want to plug this in and solve for L.

OpenStudy (anonymous):

Use the formula for time dilation, \[t=\frac{ t _{0} }{ \sqrt{1-\frac{ v ^{2} }{ c ^{2} }} }\] whre, t= proper time t0= observed time.

OpenStudy (anonymous):

\[t=\frac{ 4*365*24*60*60 }{ \sqrt{1-\frac{ 0.99 ^{2}c ^{2} }{ c ^{2} }} }\] I calculated the answer and its around\[8.99139\times10^{-7}\] but you should confirm it by calculating it again.

OpenStudy (anonymous):

the answer is in years 8.99139*10^-7 years

OpenStudy (anonymous):

or the answer is 894211107.2 seconds

OpenStudy (anonymous):

@shamim, The formula you have given(L=) that is for length contraction, not time dilation.

OpenStudy (anonymous):

Thank you :) can you help me with another problem please?

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