A space ship travels to Alpah Centauri which is about 4 light years away from earth. How far does this distance appear to you if you are on a space ship traveling at .99c?
@shamim
i think it will b the same formula
\[L=L _{0}\sqrt{1-\frac{ v ^{2} }{ c ^{2} }}\]
what do L and L0 = ?
@shamim
\[L _{o}=4 ly\]
we hv to calculate L
then what would v=?
@Compassionate
v = the velocity relative c= speed of light
c = the speed of light L0 = proper length L = length at speed v v = speed of the rocket
You want to plug this in and solve for L.
Use the formula for time dilation, \[t=\frac{ t _{0} }{ \sqrt{1-\frac{ v ^{2} }{ c ^{2} }} }\] whre, t= proper time t0= observed time.
\[t=\frac{ 4*365*24*60*60 }{ \sqrt{1-\frac{ 0.99 ^{2}c ^{2} }{ c ^{2} }} }\] I calculated the answer and its around\[8.99139\times10^{-7}\] but you should confirm it by calculating it again.
the answer is in years 8.99139*10^-7 years
or the answer is 894211107.2 seconds
@shamim, The formula you have given(L=) that is for length contraction, not time dilation.
Thank you :) can you help me with another problem please?
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