A space ship travels to Alpah Centauri which is about 4 light years away from earth. How far does this distance appear to you if you are on a space ship traveling at .99c?
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OpenStudy (anonymous):
@shamim
OpenStudy (shamim):
i think it will b the same formula
OpenStudy (shamim):
\[L=L _{0}\sqrt{1-\frac{ v ^{2} }{ c ^{2} }}\]
OpenStudy (anonymous):
what do L and L0 = ?
OpenStudy (anonymous):
@shamim
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OpenStudy (shamim):
\[L _{o}=4 ly\]
OpenStudy (shamim):
we hv to calculate L
OpenStudy (anonymous):
then what would v=?
OpenStudy (anonymous):
@Compassionate
OpenStudy (compassionate):
v = the velocity relative
c= speed of light
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OpenStudy (compassionate):
c = the speed of light
L0 = proper length
L = length at speed v
v = speed of the rocket
OpenStudy (compassionate):
You want to plug this in and solve for L.
OpenStudy (anonymous):
Use the formula for time dilation,
\[t=\frac{ t _{0} }{ \sqrt{1-\frac{ v ^{2} }{ c ^{2} }} }\]
whre, t= proper time
t0= observed time.
OpenStudy (anonymous):
\[t=\frac{ 4*365*24*60*60 }{ \sqrt{1-\frac{ 0.99 ^{2}c ^{2} }{ c ^{2} }} }\]
I calculated the answer and its around\[8.99139\times10^{-7}\]
but you should confirm it by calculating it again.
OpenStudy (anonymous):
the answer is in years
8.99139*10^-7 years
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OpenStudy (anonymous):
or the answer is 894211107.2 seconds
OpenStudy (anonymous):
@shamim,
The formula you have given(L=)
that is for length contraction, not time dilation.
OpenStudy (anonymous):
Thank you :) can you help me with another problem please?