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find the indefinite integral: ∫3x^(x)sin(x^(3))dx
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\[\int\limits3x ^{2}\sin x ^{3}dx\]
\[u=x^3\]
i know...but i want to check my ans...\[\frac{ -\cos x^ 4 }{ 4 }\] ?
i think answer will b \[-\cos x ^{3}\]
can i show details
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Did you use integration by parts?
i can show my work
oops ...can you show me the detail...? thanks
ok
let \[u=x ^{3}\]
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or,\[du=3x ^{2}dx\]
so ur given term will b\[\int\limits_{?}^{?} \sin u du=-\cos u=-cosx ^{3}\]
You can take out the 3 since its just a constant multiplied to the whole thing, so your \[u=x^3\]
no need to take 3 outside of ur integral
-_- i read it as 3x^3 xD my bad.I got the same answer.:)
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