what is the distance between 75,1200 and 120,1500 on a coordinate grid, and 75,1700 and 120,1500, all on a coordinate grid.

Question

amistre64 · Answer

are you able to find the distance that a general point (x,y) is from the origin (0,0)?

anonymous · Answer

I don't think so..

amistre64 · Answer

|dw:1368713003631:dw|

anonymous · Answer

that's why I am asking you guys

amistre64 · Answer

what do we know about right triangles?

anonymous · Answer

Not alot ...

amistre64 · Answer

well, thats sounds like you know at least a little then ... so what do you know about them? perferably something relating the lengths of the legs to find a missing length

anonymous · Answer

uhh you can find a missing length with a squared plus b squared = c squared

amistre64 · Answer

yes :)

in this case:  d = sqrt(x^2 + y^2)

so as long as we can move any 2 points so that one of them is at the origin, the x and y parts are easily determined

amistre64 · Answer

lets take the first set of points:

 75  ,  1200 and 120  ,1500  ,  we move them by subtracting like amounts
-75  -1200        -75  -1200
-----------     -----------
   0  ,   0               45    ,300
      ^^                       ^^^
    origin                 other point

anonymous · Answer

alright

amistre64 · Answer

now that we know the (x,y) parts, we only have to use them to find the distance:$$d=\sqrt{x^2+y^2}$$

anonymous · Answer

Right even more confusing

amistre64 · Answer

good luck with it then .... i find the other methods even more confusing