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Mathematics 16 Online
OpenStudy (anonymous):

find the length and midpoint of the segment joining the two given points. s(9,12)and u(-9,-12)

OpenStudy (ajprincess):

The length d can be found using the formuls \[d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\] here \(x_1=9,~x_2=-9,~y_1=12,~y_2=-12\) Does that help? @tsdsfisdifigf

OpenStudy (anonymous):

is that supposed to be my answer?

OpenStudy (anonymous):

im confused...

OpenStudy (ajprincess):

well if u plug in those values in the formula and simplify u can find the length

OpenStudy (anonymous):

a. 30;(0,0) b.27;(10.5,10) c.15;(4,9) d. 45;(-8,9)

OpenStudy (anonymous):

oh okay. lol thanks so much :)

OpenStudy (anonymous):

well actually i did when i was trying to find the midpoint. i got (0,3.5) but idk why its wrong. idk how to find the length

OpenStudy (ajprincess):

so found the length?

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

oh wait im sorry. i thought you gave me the midpoint formula. i didnt notice it was for the length. i see what you did there

OpenStudy (ajprincess):

Let us assume that the coordinates of the midpoint be (x,y). \[x=\frac{x_1+x_2}{2}\] \[y=\frac{y_1+y_2}{2}\]

OpenStudy (anonymous):

i got 36

OpenStudy (anonymous):

now i got 6.48

OpenStudy (ajprincess):

36 for the length?

OpenStudy (anonymous):

yep but now i got 6.48. i think that was for the distance. idg it

OpenStudy (anonymous):

now i got 0

OpenStudy (ajprincess):

\[d=\sqrt{(-9-9)^2+(-12-12)^2}\] \[=\sqrt{(-18)^2+(-24)^2}\]

OpenStudy (anonymous):

thank you! i had what you written down i just forgot to add them after i squared them.

OpenStudy (ajprincess):

Welcome:) so vat is d=?

OpenStudy (anonymous):

(0,0) :)

OpenStudy (anonymous):

no wait thats the midpoint lol. owells. i just needed the midpoint and length <3

OpenStudy (ajprincess):

yup. ur midpoint is right:) bt length is vat?

OpenStudy (anonymous):

30 lol

OpenStudy (ajprincess):

yup perfect:)

OpenStudy (anonymous):

:Dyay

OpenStudy (ajprincess):

good work:D

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