find the length and midpoint of the segment joining the two given points. s(9,12)and u(-9,-12)
The length d can be found using the formuls \[d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\] here \(x_1=9,~x_2=-9,~y_1=12,~y_2=-12\) Does that help? @tsdsfisdifigf
is that supposed to be my answer?
im confused...
well if u plug in those values in the formula and simplify u can find the length
a. 30;(0,0) b.27;(10.5,10) c.15;(4,9) d. 45;(-8,9)
oh okay. lol thanks so much :)
well actually i did when i was trying to find the midpoint. i got (0,3.5) but idk why its wrong. idk how to find the length
so found the length?
nope
oh wait im sorry. i thought you gave me the midpoint formula. i didnt notice it was for the length. i see what you did there
Let us assume that the coordinates of the midpoint be (x,y). \[x=\frac{x_1+x_2}{2}\] \[y=\frac{y_1+y_2}{2}\]
i got 36
now i got 6.48
36 for the length?
yep but now i got 6.48. i think that was for the distance. idg it
now i got 0
\[d=\sqrt{(-9-9)^2+(-12-12)^2}\] \[=\sqrt{(-18)^2+(-24)^2}\]
thank you! i had what you written down i just forgot to add them after i squared them.
Welcome:) so vat is d=?
(0,0) :)
no wait thats the midpoint lol. owells. i just needed the midpoint and length <3
yup. ur midpoint is right:) bt length is vat?
30 lol
yup perfect:)
:Dyay
good work:D
Join our real-time social learning platform and learn together with your friends!