Calculate the freezing point depression when 0.500 kg of ethylene glycol (C2H6O2) is added to 0.500 kg of water. Kf for water is 1.86C/m. A.3.00˚C B.30.0˚C
C. 300.0˚C

Question

Calculate the freezing point depression when 0.500 kg of ethylene glycol (C2H6O2) is added to 0.500 kg of water. Kf for water is 1.86C/m.  A.3.00˚C  B.30.0˚C 
C. 300.0˚C

australopithecus · Answer

ΔTf = - kfmB  

where

ΔTf is the freezing point depression

kb is the cryoscopic constant, and

mB is the molality of the solute.

australopithecus · Answer

sorry that should be kf not kb

australopithecus · Answer

you know how to calculate molality right?

anonymous · Answer

i tried but i failed i got 1.86

australopithecus · Answer

Molality = Moles of Solute/Kg of Solvent

anonymous · Answer

|dw:1368717231368:dw|

australopithecus · Answer

mB is the molality of the solute.
Molality = Moles ethylene glycol/Kg of water = mB

australopithecus · Answer

do you know how to calculate moles?

Moles =  grams of Compound/Molecular Mass of Compound

australopithecus · Answer

do you follow?