Question

1-sin^2x/1+cot^2x

Answer 1

what is ur question??

Answer 2

How do you solve that? I have no idea

Answer 3

it simplifies to this:
\[1-\sin ^{2} x/1+ \cot ^{2}x = \cos ^{2}x/ 1+ (\cos ^{2}x/\sin ^{2}x)= \cos ^{2} x/ (\sin ^{2}x + \cos ^{2}x)/ \sin ^{2}x \]
which is = \[\cos ^{2} x/ 1 * \sin ^{2}x/1= \cos ^{2} x * \sin ^{2}x\]

Answer 4

now...did u understand??

Answer 5

I do! Thank you so much!

Answer 6

u r welcum....do u need any help on any other problem??