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Mathematics 8 Online
OpenStudy (anonymous):

How many different 5-person subcommittees can be formed from a club having 10 members? (A)30,240 (B) 504 (C) 2,520 (d)252

OpenStudy (anonymous):

can any ine help? is integrated math

OpenStudy (anonymous):

??

OpenStudy (amistre64):

how many ways are there to pick the first person?

OpenStudy (amistre64):

or, if you have 10 pieces of candy in front of you; how many choices do you have on your first pick?

OpenStudy (anonymous):

10?

OpenStudy (amistre64):

yes :) and since youve taken 1 away, there are 9 left to choose from for the second pick ... 8 left for the 3rd pick .... you see a pattern in this yet?

OpenStudy (anonymous):

yes i do

OpenStudy (amistre64):

this selection is called "permuation", or in street talk its just "pick" 10 pick 5 is equal to 10*9*8*7*6 , the first 5 numbers from 10 but theres a catch to this value

OpenStudy (anonymous):

so basically it will be 504 then.

OpenStudy (amistre64):

there are groups from this pick that are "the same" that we need to divide out

OpenStudy (amistre64):

it would take about 120 different permuations of 5 pick 5 to show the pattern which means that there are 120 duplications to divide out 30240/120 is what we are looking for

OpenStudy (amistre64):

\[nCr=\frac{nPr}{r!}\]

OpenStudy (anonymous):

so it willll turn out to be 252 if its divided

OpenStudy (amistre64):

correct

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