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OpenStudy (anonymous):
write the expression as a single lograrithm, Express powers as factors.
ln((x/x-7))+ln((x+7/x))-ln(x^2-49)=______________
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OpenStudy (anonymous):
\[\ln \frac{ a }{ b }=\ln a - \ln b\]\[\ln ab = \ln a + \ln b\]Factor x^2 -49 and you can do it easily.
OpenStudy (anonymous):
would this be it \[(\ln(x)-\ln(x-7))+(\ln(x+7)-\ln(x))-(\ln(x+7)(x-7))\] @Anonymous1921
OpenStudy (anonymous):
Yes. And ln[(x+7)(x-7)]=ln(x+7)+ln(x-7). So you can cancel out something.
OpenStudy (anonymous):
okay so it will look like wouldn't everything be cancel?
OpenStudy (anonymous):
@Anonymous1921
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OpenStudy (anonymous):
I think -2ln(x-7) would be left. Check your calculation again. I might be wrong.
OpenStudy (anonymous):
so I got it to look like lnx-lnx-7+lnx+7-lnx-lnx-7+lnx+7
OpenStudy (anonymous):
then the lnx would be cancel and the lnx+7 would be cancel leaving -2lnx-7 ?
OpenStudy (anonymous):
ln(x)-ln(x-7)+ln(x+7)-ln(x)-ln(x+7)-ln(x-7). Oh, sorry. Everything would be cancelled out.
OpenStudy (anonymous):
really?? but the ln(x-7) doesnt get cancel out
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OpenStudy (anonymous):
so wouldnt it be -2ln(x-7)
OpenStudy (anonymous):
Oh, yeah. -2ln(x-7).
OpenStudy (anonymous):
okay thanks you for the big help!
OpenStudy (anonymous):
You're welcome :)
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