Question

Solve 4x2 + 2x - 4 = 0 by completing the square.

A. (-1 +√17)/4, (-1-√17)/4
B. (1 +√17)/4, (1-√17)/4
C. (5+√37)/2, (5 -√37)/2
D. (-1+√3)/2, (-1-√3)/2

Answer 1

Move the 4 over to the other side.
4x+2x+_=4+_
Half the number with the x and square that
2/2=1 squared= 1
Put that number in the blanks
4x2+2x+1=4+1
4x2+2x+1=5
Now factor

Answer 2

Only this one doesn't factor, so you use the quadratic formula

Answer 3

whats the answer

Answer 4

\[4x ^{2}+2x-4=0\]
divide by 4,
\[or x ^{2}+\frac{ 2 }{4 }x-1=0\]
\[x ^{2}+\frac{ 1 }{ 2 }x=1\]
adding both sides square of( 1/2)/2,i.e.,1/16
\[x ^{2}+\frac{ 1 }{ 2 }x+\frac{ 1 }{ 16 }=1+\frac{ 1 }{16 }=\frac{ 17 }{1 6 }\]
\[\left( x+\frac{ 1 }{ 4 } \right)^{2}=\frac{ 17 }{ 16 }\]
\[x+\frac{ 1 }{ 4 }=\pm \frac{ \sqrt{17} }{ 4 }\]
\[x+\frac{ 1 }{ 4 }=\frac{ \sqrt{17} }{ 4 },x=\frac{ -1+\sqrt{17} }{ 4 }\]
\[x+\frac{ 1 }{ 4 }=\frac{ -\sqrt{17} }{ 4 },x=-\frac{ 1+\sqrt{17} }{ 4 }\]