Question

evaluate

Answer 1

i got 49/4 is that correct?

Answer 2

@jazy @agent0smith @satellite73

Answer 3

I don't get why your pics are so small, please make them bigger if possible. Or just actually write it yourself like so... I'm going to write this so people can actually read it:

\[\Large \int\limits_{0}^{2} x \sqrt{ 4x^2 +9} dx\]

Answer 4

okay

Answer 5

yea thats correct

Answer 6

As long as you used u substitution with u=4x^2+9, du= 8x dx, it should be correct. 49/4 isn't correct, but it's close.

Answer 7

okay i tried again and i got 49/6

Answer 8

http://www.wolframalpha.com/input/?i=%5Cint%5Climits_%7B0%7D%5E%7B2%7D+x++%5Csqrt%7B+4x%5E2+%2B9%7D+dx

Answer 9

okay so my question has multiple choices and in them none of that has 49/6

Answer 10

there is 32/3, 15/4, 80/9 and 49/4

Answer 11

Mathematica returned 49/6

Answer 12

yea i'm guessing my teacher made a mistake

Answer 13

Refer to the attachment

Answer 14

@robtobey I already posted the wolfram alpha solution... which uses mathematica :P

Answer 15

Sorry about that.