Question

find the equcation of plane through the points p(4,4,-4),q(2,-5,-5),r(1,2,2)

Answer 1

\[\vec {pq}=?\]

Answer 2

\[\vec{pr}=?\]
then \[n=<\vec{pq}>.<\vec{pr}>\]
\[\vec n\]and one point you can write out the equation of the required plane

Answer 3

my answers was -56x+21y-23z=-48

Answer 4

is wrong

Answer 5

why

Answer 6

\[\vec{PQ} = \vec{Q} - \vec{P}\]\[\vec{PR} = \vec{R} - \vec{P}\]\[\vec{n} = \vec{PQ} \times\vec{PR}\]

Answer 7

i did that

Answer 8

still wrong

Answer 9

i find the n
then i sub p0

Answer 10

find the value

Answer 11

pq=-2,-9,-1
pr=-3,-2,6

Answer 12

pls check
then i used matrix 3*3 matrix to find the n
then i left with

Answer 13

-56x+21y-23z

Answer 14

then i sub p0 to get -48

Answer 15

-56x + 15y - 23z + 72 = 0

Answer 16

thanks