Question

A 15.0 kΩ resistor is hooked up to a 45.0 V battery in a circuit with a switch.
a.) Draw a circuit diagram for the circuit described. Label all parts and values.
b.) What is the current flowing through the resistor?
c.) What is the power dissipated by the resistor?

Answer 1

Current. 003a

Answer 2

Power dissipation .135 watt

Answer 3

Here's the drawing.
The current is given by \[\frac{ V }{ R }=I\]
Hence \[I=\frac{ 45 }{ 15000 }=3mA\] The power is given by\[P =\frac{ V ^{2} }{ R}=\frac{ 45^{2} }{15000 }=0.135W\]

Answer 4

Thanks for the explanation I understand now :)