Question

Trig question, please help finish

Answer 1

\[\large y=tanx(sinx+cosx)\]

Answer 2

\[\large y'= (tanx)(cosx+sinx)+(sinx+cosx)(\sec^2x)\]

Answer 3

is that it or can i do more ?

Answer 4

Thats the Product Rule of Differentiation, right?
so,

(f(x))(g(x)) = f'(x)g(x) + g'(x)f(x)

Answer 5

Which will give you:
y = tanx ( sinx + cosx )

y' = ((secx)^2)( sinx + cosx) + (tanx)(cosx - sinx)

Answer 6

would that be all ?

Answer 7

yes. You might have to simplify though.

Answer 8

how ?

Answer 9

I said, 'might have to'
from the looks of it, that answer is just as good.

Answer 10

do you still need help simplifying?