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Mathematics 7 Online
OpenStudy (anonymous):

Can someone help me? http://prntscr.com/159ecf

OpenStudy (anonymous):

@some_someone @Luis_Rivera

OpenStudy (anonymous):

15

OpenStudy (anonymous):

Care to explain?

OpenStudy (anonymous):

Please do not just give out the answer. Thank you:)

OpenStudy (anonymous):

Anyone want to explain...

OpenStudy (anonymous):

Sure \[\sqrt{225}\]Let's find some common factors of 225. How about 9 and 15. We know that 9 multiplied by 15 is equal to 225. So we can write \[\sqrt{225}=\sqrt{15\times 9} \]with me so far?

OpenStudy (anonymous):

We can then simplify further\[\sqrt{25 \times 9} = \sqrt{25} \times \sqrt{9}\]

OpenStudy (anonymous):

(sorry I meant 25)

OpenStudy (anonymous):

\[\sqrt{225} = \sqrt{25 \times 9} = \sqrt{25} \times\sqrt{9} = 5 \times 3 = 15\]

OpenStudy (anonymous):

Hope that helps!

OpenStudy (anonymous):

the squire root is 15 put it in a cac and then you get 15

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