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Mathematics 6 Online
OpenStudy (anonymous):

Figure I shows a piece of triangular cardboard ABC with sides 8 cm, 10cm, 12cm. D is a point on AC such that

OpenStudy (anonymous):

|dw:1368770233851:dw|

OpenStudy (anonymous):

for A)... find angle BCD

OpenStudy (anonymous):

then what can you do to find a side of a triangle if you know all three angles and one side length?

OpenStudy (anonymous):

@kryton1212

OpenStudy (anonymous):

part a ii

OpenStudy (anonymous):

sine formula?

OpenStudy (mathstudent55):

How did you get (a) (i) to be 55.8 deg?

OpenStudy (anonymous):

cos<ACB= (12^2+8^2-10^2)/(2*12*8)

OpenStudy (mathstudent55):

Ok, I got 55.771... Law of cosines. That's good.

OpenStudy (mathstudent55):

Since you now have m<ACB, and you know m<CBD = 30, you can get m<BDC

OpenStudy (dan815):

peter did u change ur picture

OpenStudy (mathstudent55):

Then with m<BDC and the opp side of 8 cm, you can use the law if sines to get CD using its opp angle of 30 deg.

OpenStudy (dan815):

|dw:1368771811921:dw|

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