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Figure I shows a piece of triangular cardboard ABC with sides 8 cm, 10cm, 12cm. D is a point on AC such that
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|dw:1368770233851:dw|
for A)... find angle BCD
then what can you do to find a side of a triangle if you know all three angles and one side length?
@kryton1212
part a ii
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sine formula?
How did you get (a) (i) to be 55.8 deg?
cos<ACB= (12^2+8^2-10^2)/(2*12*8)
Ok, I got 55.771... Law of cosines. That's good.
Since you now have m<ACB, and you know m<CBD = 30, you can get m<BDC
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peter did u change ur picture
Then with m<BDC and the opp side of 8 cm, you can use the law if sines to get CD using its opp angle of 30 deg.
|dw:1368771811921:dw|
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