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Mathematics 10 Online
OpenStudy (anonymous):

Find the indicated term for each sequence.

OpenStudy (anonymous):

a. 6, 4, 2, 0, ...a21 b. 3, -6, 12, -24, ...a18 c. 1/3, -2/9, 4/27, -8/81, ...a9 d. 5, -2, -9, -16, ...a120

mathslover (mathslover):

I will solve any one for you, which one you want?

OpenStudy (anonymous):

Can you do B?

mathslover (mathslover):

well can you first tell me whether it is GP or AP?

OpenStudy (anonymous):

I think it's AP

mathslover (mathslover):

What is the main condition for AP @LoveToDance22 ?

OpenStudy (anonymous):

It's if the sequence is adding or subtracting, right?

mathslover (mathslover):

Well, actually the main thing is the "common difference" like : 1,2,3,4,5 .... , in this sequence the common difference exists which is : 1. We have the following sequence : 3 , -6 , 12 , -24 , .... Now, can you tell me whether the common difference exists or not?

mathslover (mathslover):

@LoveToDance22 , you there?

OpenStudy (anonymous):

Sorry, stepped away for a second, Is it -2?

mathslover (mathslover):

No, well, -2 is the common ratio here. See this : 3 * -2 = -6 * -2 = 12 * -2 = -24 * -2 = 48 .... and so on

mathslover (mathslover):

That is it is a GP...

mathslover (mathslover):

getting it?

OpenStudy (anonymous):

Yeah, thanks! I can do the rest later though, g2g to school :q

mathslover (mathslover):

You have to just use the following formula : \(a_n = a * r^{n-1} \)

mathslover (mathslover):

where n = 18 , and r =common ratio = -2 and a = first term = 3

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