Question

Solve the linear equations
3x + 2y - 7 = 19 ------ (i)
4x - y + 27 = 4 --------(ii)
2x + 4y - 52 = 32 ------(iii)
find x, y and z

Answer 1

where is z in the equations above...?

Answer 2

is it the -7, +27 and -52, or the 19, 4 and 32...?

Answer 3

not sure also, that my problem also
@jack1

Answer 4

or use cramma's rule and let see what you will derive at

Answer 5

ok, assuming the 3rd number in every equation is a "z" value...
you can solve it either as a matrix or as a series of simultaneous equations (they're both pretty much the same thing in the end, just different ways of approaching it, whatever you're more comfortable with really.

anyway, i used matrix, and came up with:
x= 372/115 (approx 3.24)
y= 461/115 (approx 4)
z= -21/115 (approx -0.18)

Answer 6

thanks so much but there question is a sample question, here is what the got, am trying to use the sample to solve other questions. the sample question and working goes those:

Answer 7

Example: Solve the linear equations
3x + 2y - 7 = 19 ------ (i)
4x - y + 27 = 4 --------(ii)
2x + 4y - 52 = 32 ------(iii)
Solution: 3x + 2y - 7 = 19 --------- (i)
Eq(i) x 4 -Eq(2) x 3 1 ly – l0z = 64
Eq(2) - Eq(3) x 2 -9y + 12z = -60
3x+2y-z= 19
1ly-l0z=64
Eq (4) x 9 - Eq (5) x 11 42 Z = -84
\ Z = -2
Substituting the value of Z in eq (4) you obtain lly+20=64
l ly + 20 = 64
11 y = 44
y = 4
Substituting the values of y and z in equation
(i) You get
3x+8+2 = 19
3x = 9
x =3
\x =3,y =4 z =-2

Answer 8

can you please teach me how you solve it, step by step explanation