solve the deferential equation dy/dx=4x^4y^4 with the condition that y(2)=2 the solution is y=________?
This is what you call a "separable" differential equation, means expressions involving y and x may be separated into factors. Let's demonstrate... also, pretend that dy and dx are expressions in their own right and may be multiplied, divided, or cancelled... \[\Large \frac{\color{red}{dy}}{\color{blue}{dx}} = 4x^4y^4\] Multiply both sides by dx, the left-side dx cancels, giving you... \[\Large \color{red}{dy} = 4x^4y^4\color{blue}{dx}\] Next, divide both sides by y^4, cancelling out the y^4 on the left \[\Large \frac1{y^4}\color{red}{dy}=4x^4\color{blue}{dx}\] then just integrate both sides...\[\Large \int\frac1{y^4}\color{red}{dy}=\int4x^4\color{blue}{dx}\]
i saw what you did there... ;)
so -4/y^5=4x^5/5
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