How would I do this? @Compassionate (wait a second, I have to attach the snapshot)
You need to solve each one: First: 3x^2 (3x^2) = 9x^4 Second: (3x^3)^2 (x^2) = 3x^6 (x^2) = 3x^8
expression 2's exponents are greater than expression 1's
\[(3x^2)3x^2 = 9x^4\] \[(3x^2)^2(x^2) = 9x^4(x^2) = 9x^6\]
Because \(\Large\color{red}{\mathbb{3^2 * x^2 * x^2}}\) for the first one.
OK.. wait..whaa?
You asked me to do the problem and I did.
I'm still slightly confused.
About?
So the first one simplified is \[3^2 * x^2*x^2\] , right?
(3x^2)3x^2 = 9x^4
Okay, how would I go around to simplifying the second one?
(3x^2)^2(x^2) 3^2 * x^2 [We must multiply everything inside the parentheses by the power of 2] 9x^4(x^2) [We must add the exponents] 9x^4 + 2 9x^6
Ok, I get it now. Thanks :)
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