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Mathematics 6 Online
OpenStudy (anonymous):

9. Use the discriminant to find the number of real solutions of the following quadratic equation: 9x2 + 6x + 1= 0. A. no real solutions B. 1 real solution C. 2 real solutions D. 3 real solutions

OpenStudy (campbell_st):

the discriminant is \[\Delta = b^2 - 4ac\] in your question a = 9, b = 6 and c = 1 the conditions Discriminant > 0, 2 unequal roots, if its a perfect square such as 4, 16, 25, the roots are rational Discriminant = 0, 2 equal roots sometimes called 1 root Disriminant < 0 no real roots, hope this helps.

OpenStudy (anonymous):

what would the answer be? @campbell_st

OpenStudy (campbell_st):

what value did you get for the discriminant when you substituted..?

OpenStudy (anonymous):

could i just have the answer please im short on time and this is my last question

OpenStudy (anonymous):

@campbell_st

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