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Suppose H(x)=(6x-5)^2
Find the 2 functions f and g such that (f o g)(x)=H(x)
Neither function can be the identity function.
(There may be more than one correct answer.)
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OpenStudy (campbell_st):
why not g(x) = 6x - 5
f(x) = (x)^2
OpenStudy (anonymous):
oh okay!
OpenStudy (anonymous):
I hope your right :D
OpenStudy (campbell_st):
well here is the method
what is f(g(x)) = (g(x))^2
= (6x - 5)^2
OpenStudy (anonymous):
right
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OpenStudy (campbell_st):
its means find a function g(x) substitute it into a function f(x) so that you get
H(x) = (6x - 5)^2
you could have g(x) = (6x - 5)^2/3
f(x) = x^3
you'll get the same answer.
OpenStudy (anonymous):
but you said x^2 not x^3
OpenStudy (anonymous):
oh nevermind haha. that was an example right?
OpenStudy (campbell_st):
correct.... thats why the question says... there may be more than 1 solution.
OpenStudy (anonymous):
okay so the answer is g(x) =6x-5 and f(x) x^2... thanks