Question

find the center, transverse axis, vertices, foci, and asymptotes.
x^2-4y^2=64

Answer 1

the center is at (0,0)
and is transverse on the y ??

Answer 2

i got the new equation to be x^2/64 - y^2/16 = 1

Answer 3

a is 8 and b is 4 and c is sqrt of 80 = 4sqrt 5

Answer 4

you kinda all over the place with this one. lemme try to help you

Answer 5

that would be helpful!

Answer 6

for sure the center is (0,0) but I am not sure about my new equation

Answer 7

hand over the medal, and we can begin lml

Answer 8

wait isnt it you help me first and then I give the medal???

Answer 9

yea. but people forget. trust tho. I always get the answer.

Answer 10

don't do it, it's a trick lol

Answer 11

I could always undo it

Answer 12

how did you get the center as (0,0)?

Answer 13

by setting the 64 to 1 and its quite sure that its (0,0) and it kinda tells you its (0,0)

Answer 14

also by setting the equation to 1 I would get the top equation that I said before and from there I could get my a and b and once I got my a and b I found c but not 100% sure that that is the right equation

Answer 15

and its transverse on the y because a is greater then b

Answer 16

@geishaology did you quit on me??

Answer 17

well so much for helping me I might just give it to @iamlegend