Find the equation of a line through (4, -3) that is parallel to the line that passes through these points (-4,7) and (2,4). Write your answer in standard form (Ax + By = C). Show all your work. I'm really stuckkkk
To find the slope between the 2 points (x₁,y₁) and (x₂,y₂), use: \[m = \frac{ y₂ - y₁ }{ x₂ - x₁ }\] If two lines are parallel, their slopes are the same.
But I need to find the equation of the line..
Once you know the slope, you can use the point-slope formula to find the equation: \[(y-y₁) = m(x-x₁)\]
Then you can solve it for standard form
so would my formula to find the slope be (4-7)/2- -4)
Yup, that would be the slope (m).
My answer comes up with -1/2 for the slope is that correct?
Yes, that is correct.
What do I do next? Sorry I'm just really stuck
Now that you have the slope, plug it into the equation (y-y₁) = m(x-x₁) Where (x₁,y₁) is any point on the new line.
Wait how do I plug it into the equation?
Put -1/2 in place of m, 4 in place of x₁, and -3 in place of y₁.
So it would now be y- -3 = -1/2 (x-4)?
Yes.
Now put it into standard form by placing the x and y terms on the left, and the constants on the right.
I'm stuck? what do you mean?
(Ax + By = C). this is the example of standard form
y + 3 = -(1/2)x + 2 y + (1/2)x = -1 2y + x = -2
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