Mathematics
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OpenStudy (anonymous):
What is the simplified form of ... (picture in comments)
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OpenStudy (anonymous):
mathslover (mathslover):
Can you factor out 48 first?
OpenStudy (anonymous):
What do mean?
OpenStudy (anonymous):
you
OpenStudy (anonymous):
What do you mean*
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mathslover (mathslover):
I mean, what are the factors of 48?
OpenStudy (anonymous):
2, 3, 4, 6, 8, 12, 16, and 24
mathslover (mathslover):
Right, so I can write 48 = 16*3 also? right... ?
OpenStudy (anonymous):
Yes.
mathslover (mathslover):
Now, let us write this :
\(\sqrt{48 n^9} = \sqrt{16 * 3 * n^9} \)
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OpenStudy (anonymous):
Ok
mathslover (mathslover):
Now, can I write \(\large n^9 \space \text{as} \space n^8 * n \) ?
OpenStudy (anonymous):
Yes
mathslover (mathslover):
Now, \(\large \sqrt{16*3 * n^8 * n }\)
What is the square root of 16 and that of n^8 ?
OpenStudy (anonymous):
the suare root of 16 is 4, and i think the square root of n^8 is n, but I'm not sure.
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mathslover (mathslover):
yes, the square root of 16 is 4 but , square root of n^8 = \(\large (n^8)^{\cfrac{1}{2}} \)
Now multiplying 8 * 1/2 = n^4
so it is n^4
OpenStudy (anonymous):
Ohh, ok
mathslover (mathslover):
or
n^8 = n * n * n * n * n * n * n* n
square root of this will be : n * n * n * n
mathslover (mathslover):
You get now : \(4n^4 \sqrt{3n}\)
OpenStudy (anonymous):
OKay