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Mathematics 19 Online
OpenStudy (anonymous):

What is the simplified form of ... (picture in comments)

OpenStudy (anonymous):

mathslover (mathslover):

Can you factor out 48 first?

OpenStudy (anonymous):

What do mean?

OpenStudy (anonymous):

you

OpenStudy (anonymous):

What do you mean*

mathslover (mathslover):

I mean, what are the factors of 48?

OpenStudy (anonymous):

2, 3, 4, 6, 8, 12, 16, and 24

mathslover (mathslover):

Right, so I can write 48 = 16*3 also? right... ?

OpenStudy (anonymous):

Yes.

mathslover (mathslover):

Now, let us write this : \(\sqrt{48 n^9} = \sqrt{16 * 3 * n^9} \)

OpenStudy (anonymous):

Ok

mathslover (mathslover):

Now, can I write \(\large n^9 \space \text{as} \space n^8 * n \) ?

OpenStudy (anonymous):

Yes

mathslover (mathslover):

Now, \(\large \sqrt{16*3 * n^8 * n }\) What is the square root of 16 and that of n^8 ?

OpenStudy (anonymous):

the suare root of 16 is 4, and i think the square root of n^8 is n, but I'm not sure.

mathslover (mathslover):

yes, the square root of 16 is 4 but , square root of n^8 = \(\large (n^8)^{\cfrac{1}{2}} \) Now multiplying 8 * 1/2 = n^4 so it is n^4

OpenStudy (anonymous):

Ohh, ok

mathslover (mathslover):

or n^8 = n * n * n * n * n * n * n* n square root of this will be : n * n * n * n

mathslover (mathslover):

You get now : \(4n^4 \sqrt{3n}\)

OpenStudy (anonymous):

OKay

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